If Magnet Pull's out-of-battle effect rolls a Steel-type encounter, how does it choose between multiple Pokemon?

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From Pokémon Emerald onwards, if a Pokémon with Magnet Pull is in the first place in the party (even if fainted), then there is a 50% chance the game will force an encounter with a Steel-type Pokémon, if one is possible.

-Bulbapedia’s page forMagnet Pull. The same question goes for Static and its effect on Electric types.

I’m confused. In Omega Ruby, both Mawile and Aron live in Granite Cave. Both can be found in B2F of the cave; if I have Magnet Pull, how does it affect the spawn rates if one of these encounters is triggered by Magnet Pull? Given that this means other possible encounters are thrown out the window for this particular encounter that the abilitydidtrigger, what are the new rates?

Aron is normally higher than Mawile at a 30%-20% ratio, while in hordes it’s even harder at 35% to only 5%.

If looking for Mawile might potentially be easy maybe I’ll look for one. I already have Aron.

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The previous answer is a bit of guess, so does mine, but let us analyse this deeply.

Without Magnet pull:

So basically percentage of encountering all Pokemons except Aron is 70%.

When magnet pull is affected,

When you add all the values, it will be 99.99 which is approx 100%.

In Area 3 in Granite Cave, wheretwo steel types,both Mawile and Aronare found,

Without Magnet Pull,

Possibility of encountering Steel types = 30 + 10 = 40%, non-steel types = 60%

With Magnet Pull, (Aron + Mawile = 50%)

When you add all the values, it will total to 100%

I am not sure in the case where the probability of encountering a steel type is above 50%, whether it reduces to 50% or not. However, it is a guess.

Hope this helps :)

I think we just gotta do a little math.Bulbapediasays 50% chance to force steel type encounter. Steel types= 2Chance for Mawile and Aron = 50/2 = 25%Thus both have 1/4 chance of appearing if leading with magnet pull Pokémon. Please try this and tell me if it helps!