What is the catch rate of this?

In percent, what is the catch rate of a Pokémon with an official catch rate of 3 when it has 1 HP, it’s asleep or frozen, and you are using an Ultra Ball or any other ball that doubles your chances?

Pleaselog inorregisterto add a comment.

Well, here is the formula:

So, when we personalize this to our dilemma, it is:

(((3 x HP Max - 2 x 1) x 3 x 2) / 3 x HP Max) x 2

Now - since you didn’t give us the HP Max (a very important part of the equation) I will assume it’s 150. I’ll edit the answer once you give it to us, but just so you know. :3

Now the equation is:(((3 x 150 - 2 x 1) x 3 x 2) / 3 x 150) x 2

The equation is now:((448 x 3 x 2) / 3 x 150) x 2

448 (number from previous bracket) x 3 (Base Catch Rate) =1,3441,344 (number from above) x 2 (Ultra Ball) =2,688

The equation is now:(2,688 / (3 x 150)) x 2

3 x 150 (Max HP) =450

The equation is now:(2,688 / 450) x 2

2,688 / 450 (both numbers from previous equations) =5.973333 (rounded to 6)6 (number from above) x 2 (SLP or FRZ) =12

So, the catch rate for the Pokemon with that criteria with the assumption of Max HP 150, the answer is12.

Hope I helped. :)